2x(x+5)-3(x^2+2x-1)=9-5x-x2

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Solution for 2x(x+5)-3(x^2+2x-1)=9-5x-x2 equation: 



2x(x+5)-3(x^2+2x-1)=9-5x-x2

We move all terms to the left:

2x(x+5)-3(x^2+2x-1)-(9-5x-x2)=0

We add all the numbers together, and all the variables

-(-5x-1x^2+9)+2x(x+5)-3(x^2+2x-1)=0

We multiply parentheses

-(-5x-1x^2+9)+2x^2-3x^2+10x-6x+3=0

We get rid of parentheses

1x^2+2x^2-3x^2+5x+10x-6x-9+3=0

We add all the numbers together, and all the variables

9x-6=0

We move all terms containing x to the left, all other terms to the right

9x=6

x=6/9

x=2/3

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